Question

In a two-digit number, the digit at the units place is double the digit in the tens place. The number
exceeds the sum of its digits by 18. Find the number.​

Answer 1

Answer:

24

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Step-by-step explanation:

Refer to the attachment

Answer 2

Step-by-step explanation:

Let the ten's digit be x and units digit be y

1st condition

x = 2y --------(1)

2nd condition

10x + y = x + y + 18

Therefore, 10x - x + y - y = 18

9x = 18

x = 18/9

x = 2 ----------(2)

From 1 and 2

2 = 2y

y = 2/2

y = 1

Therefore, original number is

10x + y

= 10(2) + 1

= 20+1

= 21