Question

:. In a two-digit number, the digit at the units place is double the digit in the tens place. The numbe
exceeds the sum of its digits by 18. Find the number.​

Answer 1

Answer:

Let the digit in the tens place of the number be x. The digit in the units place of the number = 2x ∴ The number = 10(x) + 2x = 12x Sum of the digits = x + 2x = 3x Given that the number exceeds the sum of its digit by 18. ⇒ 12x = 3x + 18 ⇒ 9x = 18 ⇒ x = 2 Therefore, the digit in the tens place is 2 and the digit in the units place is (2 x 2) i.e. 4. So, the number is 24.

Step-by-step explanation:

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Answer 2

Answer:

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