Math, asked by lakshit51, 1 year ago

IN A TWO DIGIT NUMBER, THE DIGIT AT THE UNITS PLACE IS THRICE THE DIGIT IN THE TENS PLACE .THE NUMBER EXCEEDS THE SUM OF ITS DIGITS BY 27. FIND THE NUMBER.​

Answers

Answered by antareepray2
31

Let the number be 10x + 3x = 13x, then;

13x = x + 3x + 27

or, 13x = 4x + 27

or, 9x = 27

or, x = 3

Hence, the number is 10(3)+3(3) = 39

HOPE THIS COULD HELP!!!

Answered by nishantmahapatra2009
1

Answer:

39

Step-by-step explanation:

10x+3x=3x+x+27

=> 9x=27

=>x=27/9

=>x=3

the number = 10*3+3*3=39

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