IN A TWO DIGIT NUMBER, THE DIGIT AT THE UNITS PLACE IS THRICE THE DIGIT IN THE TENS PLACE .THE NUMBER EXCEEDS THE SUM OF ITS DIGITS BY 27. FIND THE NUMBER.
Answers
Answered by
31
Let the number be 10x + 3x = 13x, then;
13x = x + 3x + 27
or, 13x = 4x + 27
or, 9x = 27
or, x = 3
Hence, the number is 10(3)+3(3) = 39
HOPE THIS COULD HELP!!!
Answered by
1
Answer:
39
Step-by-step explanation:
10x+3x=3x+x+27
=> 9x=27
=>x=27/9
=>x=3
the number = 10*3+3*3=39
Similar questions