Math, asked by adirawat604, 1 year ago

in a two digit number the digit at units place is double the digit in the tens place the number exceed the sum of its digit by 18 find the number

Answers

Answered by sijasubbiah
8
Hey

Here is your answer,

Let the tens digit be x.

The digit in the units place is 2x.

Number = 10x + 2x

Given:
(x + 2x) + 18 = (10x + 2x)

∴ 3x + 18 = 12x

12x - 3x = 18

9x =18

x = 182 = 2

The digit in the tens place is 2.

The digit in the units place is twice the digit in the tens place.
The digit in the units place is 4.

Therefore, the number is 24.

Hope it helps you!
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