Question

In a two digit number the digit in the tens place is four times the digit in the units place if the sum of the digit is 10 find the number

Answer 1

Step-by-step explanation:

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Answer 2

$\textbf {\underline {\underline {Step-By-Step\:Explanation:-}}}$

$\textbf {\underline {Given:}}$

• The given number is of two digits. The tens place no. is 4 times the digit in it's unit place.
• Sum of the digits is 10

$\textbf {\underline {To\:Find:}}$

• The two digit number

$\huge\underline\green {\tt Solution:}$

Let the unit place no. be ' P ' and tens place be ' S '

It is given that the unit place number is 4 times the number in tens place. So,

P = 4S

Also,

Sum of their digits = 10

So,

P + S = 10

4S + S = 10

➡ 5S = 10

➡ S = $\dfrac {10}{5}$

•°• S = 2

Now,

➡ To find P

Put the value of S in :-

P = 4S

➡ P = 4 × 2

•°• P = 8

Therefore,

Value of x and y are 2 and 8, respectively.

The number formed is 82

Answer: 82