In a two digit number the digit in the tens place is four times the digit in the unit place if the sum of the digit is 10 find the number
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is 28
Step-by-step explanation:
Let n and 4n be the ten’s digit and the one’s digit, respectively. Then
Let n and 4n be the ten’s digit and the one’s digit, respectively. Thenn+4n=10
Let n and 4n be the ten’s digit and the one’s digit, respectively. Thenn+4n=105n=10
Let n and 4n be the ten’s digit and the one’s digit, respectively. Thenn+4n=105n=10n=2
Let n and 4n be the ten’s digit and the one’s digit, respectively. Thenn+4n=105n=10n=24n=8
Let n and 4n be the ten’s digit and the one’s digit, respectively. Thenn+4n=105n=10n=24n=8Then the number is 28
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