Question

In a two-digit number, the digit in the unit's place is more than twice the digit in ten's place by 1. If the digits in the unit's place and the ten's place are interchanged, difference between the newly formed number and the original number is less than the original number by 1. What is the original number ?

Answer 1

Answer:

The original number is 37

Step-by-step explanation:

Let Number at unit's place as y and ten's place as x

So, The number is 10x + y

According to the question

y = 2x + 1 ________equation 1

(10y + x)-(10x + y)= 10x + y - 1

=> 10y + x - 10x - y= 10x + y - 1

=>10y + X - 10x - y - 10x - y + 1= 0

=>8y-19x= -1 ________equation 2

Putting equation 1 in 2

=>8(2x + 1)-19x= -1

=>16x + 8 - 19x = -1

=>-3x = -9

=>x= 3

y= 2(3) + 1

=> y= 6+1= 7

Number = 10(3) + 7= 37

WE HAVE USED SUBSTITUTION METHOD.