in a two digit number the digit in unit place is twice the digit in tenth place if 27 is added to it digits are inverse find the number
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Given :-
- In a two digit number digit in units place is twice the digit in the tens place.
- If 27 is added to the number its digits are reversed.
Solution :-
Let ,
➣ Digit in tens place = x
➣ Digit in ones place = 2x
➟ Required number = 10x + 2x = 12x
➟ Number obtained by interchanging the digits ,
= 10(2x) + x =21x
According to the question ,
➤ Required number = 36
Answered by
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- In a two digit number the digit in unit place is twice the digit in tenth place if 27 is added to it digits are inverse find the number.
- In a two digit number the digit in unit place is twice the digit in tenth place if 27 is added to it digits are inverse.
- Find the number.
- Let x denote the digit in the tenth place and y denote the digit in unit place.
- So, the number may be written as x y 10 + in the expanded form. (just like 35= 10(3) +5)
- When the digits are reversed, x becomes the digit in unit place and y becomes the digit in the tenth place.
- The changed number, in the expanded form is 10 y + x.
▪️According to the first condition, we have,
▪️Also, by second condition, we have,
▪️That is,
- Adding equations (1) and (2), we get x= 3.
- Substituting x 3 = in the equation (2), we get y = 6.
- Thus, the given number is,
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