Math, asked by rgupta96533, 8 months ago

in a two digit number the digit in unit place is twice the digit in tenth place if 27 is added to it digits are inverse find the number​

Answers

Answered by Ataraxia
5

Given :-

  • In a two digit number digit in units place is twice the digit in the tens place.
  • If 27 is added to the number its digits are reversed.

Solution :-

 Let ,

  ➣  Digit in tens place = x

  ➣  Digit in ones place = 2x

  ➟ Required number = 10x + 2x = 12x

  ➟ Number obtained by interchanging the digits ,

                                      = 10(2x) + x  =21x

   According to the question ,

       \hookrightarrow \sf 12x+27 = 21x\\\\\hookrightarrow 21x  - 12x = 27\\\\\hookrightarrow 9x = 27 \\\\\hookrightarrow \bf x = 3

   

  ➤ Required number = 36

 

Answered by Anonymous
9

_______________________________

\huge\red{\underline{{\bf Question : }}}

  • In a two digit number the digit in unit place is twice the digit in tenth place if 27 is added to it digits are inverse find the number.

\huge\red{\underline{{\bf Answer : }}}

 \bf\large{\underline\blue{Given:-}}

  • In a two digit number the digit in unit place is twice the digit in tenth place if 27 is added to it digits are inverse.

 \bf\large{\underline\green{To\: Find:-}}

  • Find the number.

 \bf\large{\underline\orange{Solution:-}}

  • Let x denote the digit in the tenth place and y denote the digit in unit place.

  • So, the number may be written as x y 10 + in the expanded form. (just like 35= 10(3) +5)

  • When the digits are reversed, x becomes the digit in unit place and y becomes the digit in the tenth place.

  • The changed number, in the expanded form is 10 y + x.

▪️According to the first condition, we have,

 \sf\large\blue{⇝y = 2x \: which \: is \: written \: as \: }

 \sf\large\blue{⇝2x - y = 0 ....... (1) }

▪️Also, by second condition, we have,

 \sf\large\pink{⇝(10 + x) - (10x + y) = 27}

▪️That is,

 \sf\large\pink{ ⇝- 9x + 9y = 27 ⟼ - x + y = 3.......(2)}

  • Adding equations (1) and (2), we get x= 3.

  • Substituting x 3 = in the equation (2), we get y = 6.

  • Thus, the given number is,

{\boxed{{\bf{(3×10)+6=36}}}}

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