Question

In a two digit number the digit in units place is twice the digit in tens place .If 27 is added to its digits are reversed.Find the number.

pls give me and with the explanation..​

who will answer I will mark brainliest...,​

Answer 1

Answer:

36

Step-by-step explanation:

let the number be xy.

y = 2x (units place is twice the digit in tens place) --------> 1

10x + y + 27 = 10y + x ( 27 is added to it digits are reversed)

10x + y + 27 -10y - x = 0

10x + y  -10y - x =  -27

9x - 9y = -27

9x - 9 * 2x = -27  (from statemnet 1)

9x - 18x = -27

-9x = -27

 x = -27/-9  = 3

 y = 2x = 2 * 3 = 6

the required number is 36

Answer 2

Answer:

36

Step-by-step explanation:

Let the digit in tens place of the number be x.

Then, the digit at units place of the number = 2x.

Thus, the number = 10(x) + 2x = 12x

Number formed by Interchanging = 21x.

Given that If 27 is added to its digits are reversed.

⇒ 12x + 27 = 21x

⇒ 27 = 9x

⇒ x = 3

Thus, Required number = 12(3) = 36.

Hope it helps!