in a two digit number the digit of tens place is three times of the digit of unit place the difference of the original and the number with interchanged digits is 54 find the original number
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2
Answer:
93
Step-by-step explanation:
let the two digit number=ab
tens digit=a
ones digit=b
ab=10a+b
ba-10b-a
ab-ba=9(a-b)
54=9(a-b)
6=a-b
6+b=a........equation1
let b = x
a=3x
3x-x ........equation2
merging eq 1&2
3x-x=6
2x=6
x=3
b=3
a=6+b=6+3=9
hence the req no.=93
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