Question

In a two digit number, the digit of the unit place is double the digit in the tens place.the number exceeds the sum of its digit by 18. Find the number.

Answer 1

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Here is your answer---

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Let the once digit be y and tens digit be x
Thus, Number = 10x + y
                       
According to the question,
                 y = 2x  -----------------------------------------------eq(i)
Also,
    10x + y = x + y 18                  { As per as question}
    10x - x = y - y + 18
      9x = 18
         x = 2

Putting the value of x in eq(i)
   We get,
    y = 2 * 2                                {Since, y = 2x}
     y = 4

Thus, Number = 10x + y
                         = 10(2) + 4
                         = 20 + 4
                         = 24

Thus, the Two - Digit  Number is 24.

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