Question

In a two - digit number , the digits at the units place is thrice the digit in the tens place.The number exceeds the sum of its digits by 27.Find the number

Answer 1

Answer:

The number is 39

Step-by-step explanation:

Let the digit at ten's place be 'x', then the digit at unit's place will be 3x.

Then the number will be 10x + 3x = 13x

and sum of the digits = x + 3x = 4x

Given that the number exceeds the sum of digits by 27.

ie, 13x = 4x + 27

9x = 27

x = 27/9 = 3

ie, the ten's digit is 3.

Then the unit's digit = 3*3 = 9

So the number is 39