Question

In a two-digit number, the first digit is 5 less than the second digit. The number itself is three times the sum of its digits. What is the number?

Answer 1

Answer:

27

Step-by-step explanation: THIS MAY SEEM LONG BUT TAKE A DEEP BREATH & CHILL IT'S SUPER SIMPLE

taking the second digit as 'x'

as per question the first digit is 'x-5'

therefore putting this in the one, tens, hundreds form

u multiply the first digit by 10 and the second by 1

therefore,

10(x-5) + 1(x)

now you have that the 2-digit number is equal to twice the sum of the digits,

so

10(x-5) + 1(x) = 3 [ (x-5) + (x) ]

on solving

10x - 50 + x = 3 (2x - 5)

11x -50 = 6x - 15

taking 6x on the right and -50 on the left

11x - 6x = 50 - 15

5x = 35

therefore x = 7

now substituting this value we get that the number is

27

yay!!!

P.S.

This is my first answer.

Answer 2

Answer:

First digit is 2

Second digit is 7

Sum of both digits: 2+7=9

Three times the sum:3*9=27

The number is 27

Step-by-step explanation: