In a two digit number the one's digit is 3 times the ten's digit. If 10 is added to the 2 times of the number, its digits interchange their places in the new number. Find the number
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Let the two numbers be x and y
x = 3y ( given )
( 10x + y ) + ( 10y + x ) = 88 (given )
11x + 11y = 88
x + y = 8
Implies, 3y + y = 8
y = 2 and x = 6
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