Question

In a two digit number. The ones digit is 3 times the tens digit,if 10 is added to 2 times of the number ,it's digits interchanges their places in new number find the number

Answer 1

Let the 2 digit no. be =10x + y
where y is the unit place digit and x is the tens place digit.
So it's reverse will be = 10y+x

ATQ
y = 3x
2(10x +y) +10 = 10y + x
put y = 3x in the above equation
2(10x + 3x) + 10 = 10*3x + x
26x + 10 = 31x
5x = 10
x=2
y = 3x =6
therefore the no is 10x +y = 20+6 =26

Answer 2

Answer:

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