Question

in a two-digit number, the ones digit is half the tens digit . When the digits are reversed the number reduces by 36. Find the number.
The best answer I will mark as the braibliest​

Answer 1

Answer:

Let the ones digit be 'x'

and the tens digit be 'y'

Thus, the number is "10y+x".

ATQ: 2x=y (1ST CASE)

ATQ:10y+x–(10x+y)=36 (2ND CASE)

10y+x–10x–y=36

9y–9x=36

or y–x=4

2x–x=4

=>x=4

So, y=8 (∵ y=2x)

Therefore, the number is : "84"

Answer 2

Answer:

84

Step-by-step explanation:

let the original no. be 10x+y.

no. formed after reversing=10y+xa

ATP,

10x+y=10y+x+36

10x+y-10y-x=36

9x-9y=36

9(x-y)=36

x-y=36/9

x-y=4

Number=84(one's digit is half of ten's digit)