Question

in a two digit number the ones digit is twice the tens digit the difference of the squares of the digits exceeds the larger digit by 40 find the two digit number​

Answer 1

Answer:

84

Step-by-step explanation:

let the unit digit be x

∴digit at tenths place =2x

as per question,

(2x)²-x²=2x+40

4x²-x²=2x+40

3x²=2x+40

3x²-2x-40=0

3x²-12x+10x-40=0

3x(x-4)+10(x-4)=0

(x-4)(3x+10)=0

either                                                                         or

x-4=0                                                                  3x+10=0

x=4                                                                      3x= -10

                                                                            x=-10/3

we know x is a digit so it cannot be in fraction or be negative

∴x=4

∴digit at tenths place =2 (4)

                                     =8

∴the no. is 84

Answer 2

Answer:

up answer is correct