Question

in a two digit number the product of the digits is 18 and their sum is 9 find the number help me I am waiting with step by step explanation ​

Answer 1

Answer:

63 or 36

Step-by-step explanation:

xy=18,

x+y=9

y=9-x

x(9-x)=18

9x-x^2=18

x^2–9x+18=0

x^2–3x-6x+18=0

x(x-3)-6(x-3)=0

(x-6)(x-3)=0

x=6 or 3

If x=6

x+y=9

y=9–6=3

If x=3

x+y=9

y=9–3=6

So the two digits number is either 63 or 36

Hope this answer will help you .

Answer 2

Step-by-step explanation:

here

the two digit number be x and y

A. T. Q

two digit number the product of the digits is 18

i.e x. y=18..............(1)

again,

the sum of two digit be 9

i.e x +y =9

or, y = 9-x............(2)

equation(2) put in equation (1) we get.

x(9-x) = 18

9x -x^2 =18

or, x^2 -9x +18 = 0

or, x^2 -6x-3x +18 =0

or, x(x-6) -3(x-6) =0

or, (x-3) (x-6) =0

Either x-3 =0

x=3

and

x-6=0

x = 6

Now, the value of x=6 put in equation (2)we get

y = 9-6 or, y =3

again,

x= 3

y = 9-3or, y=6

now, 10x+y = 10.3+6 =30+6 =36

and 10y+x =10.6+3=60+3=63

so, the number be 36or63