In a two digit number , the sum of both digit is 6.If 18 is subtracted from the number ,the digit interchange its places. Find the number
Answers
Answered by
101
hey!
let the number be 10x+y
units digit = y
ten's digit = x
According to question -
x + y = 6 ------ > 1 equation
(10 x + y )- 18 = 10 y + x
9x - 9y = 18 ( dividing by 9 )
x - y = 2 ----> 2 equation
solving 1 and 2 equations we get,
x = 4
y = 2
so the required number = 10 * 4 + 2
= 42
hope this helps you
please mark it as brainliest answer
let the number be 10x+y
units digit = y
ten's digit = x
According to question -
x + y = 6 ------ > 1 equation
(10 x + y )- 18 = 10 y + x
9x - 9y = 18 ( dividing by 9 )
x - y = 2 ----> 2 equation
solving 1 and 2 equations we get,
x = 4
y = 2
so the required number = 10 * 4 + 2
= 42
hope this helps you
please mark it as brainliest answer
Answered by
37
Hey!!!....Here is ur answer
let first digit is x and second is y
then the number is 10x+y
According to question...
x+y=6 -----eq 1
10x+y-18=10y+x
9x-9y=18
x-y=2 ---- eq2
solving eq 1 ans eq 2
x=4 and y=2
Then the number is 10x+y=10×4+2=42
So the number is 42
Hope it will help you
let first digit is x and second is y
then the number is 10x+y
According to question...
x+y=6 -----eq 1
10x+y-18=10y+x
9x-9y=18
x-y=2 ---- eq2
solving eq 1 ans eq 2
x=4 and y=2
Then the number is 10x+y=10×4+2=42
So the number is 42
Hope it will help you
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