Math, asked by rakrshberma019822, 9 months ago

In a two digit number, the sum of digits is 9and the digit at tens place is twice the digit at ones place. find the number. ​PLEASE GIVE ME ANSWER

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Answers

Answered by akshiitaa
7

Step-by-step explanation:

Let the ones digit be x,

Then, tens digit will be 2x.

a/q 2x + x = 9

3x = 9

x =9/3

x = 3

Ones digit = x = 3

Tens digit =2x

=2 × 3

= 6

The number = 63.

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