Question

in a two digit number,the sum of the digit is 5 more than the unit digit. the difference between the original number and the sum of digit is 10 more than the number formed by reversing the digits. then find the difference between the digits.​

Answer 1

$<b>Answer :</b>$

53

$<b>Step-by-step explanation :</b>$

let say number = 10x + y

x + y = 5 + y

x = 5

10x + y - (x + y) = 10 + 10y +x

9x = 10 + 10y + x

8x = 10y + 10

8*5 = 10y + 10

40 = 10y + 10

10y = 30

y = 3

$\bigstar {\boxed{\bf {Number \:= \:53}}}$