Question

in a two digit number the sum of the digit is 7 if the number with the order of digits it was it founded greater than twice the digits of the original number find the number​

Answer 1

Answer:

25

If we interchange the digits of 25 it will be 52.

52>25×2=50

Answer 2

Answer:

The required number is 43.

Step-by-step explanation:

Consider the :

The number as - 10x + y

Given :

x + y = 7

y = 7 - x

Reversed number = 10y + x

10y + x = 28 + 2y

To Find :

The number.

Solution :

We have :

⇒ y = 7 - x       ...Eq(1)

So,

$\sf\\ \\\implies 10(7 - x) + x = 28 + 2(7 - x)\\ \\ \\ \implies 70 - 10x + x = 28 + 14 - 2x\\ \\ \\ \implies 70 - 9x = 42 - 2x\\ \\ \\ \implies 28 = 7x\\ \\ \\ \implies x = 4$

Now,

$\sf\\ \\\implies y = 7 - x\\ \\ \\ \implies y = 7 - 4\\ \\ \\ \implies y = 3$

New Number :

$\sf\\ \\\implies 10x + y\\ \\ \\ \implies 40 + 3\\ \\ \\ \implies 43$

∴ The required number is 43.