Question

in a two digit number the sum of the digit is 7. then the sum of number and the number obtained by interchanging the digit is

Answer 1

Let the two digit no be 10x +y
A. To. Q
x+y=7
To find:10x+y +10y+x
=11x+11y
=11(x+y)
=11(7)
=77

Answer 2

Answer:

25

Step-by-step explanation:

let digit at ones place=x and

digit at tens place=y

So, the number will be 10y+x

x+y=7 ....(1)

reverse digit will be represented as, 10x+y

So,

(10x+y)-(10y-x)=27

9x-9y=27

x-y=3 ....(2)

Adding equation (1) and (2)

2x=10

x=5

substituting in equation (1)

y=7-5

=2

Thus, the number will be 25