Question

in a two digit number the sum of the digits is 6. The difference between the number of its digits are reversed and original number is 18. Find the numbers

Answer 1

Let tenth digit of an original number be x & unith digit be y so 

original number would be 

                                     10x+y

when digits are reversed new number would be x+10y

 

10x+y = x+10y+18

9x -9y =18

x-y=2.....eqn 1

 

sum of digits is 6 so

                                    x+y=6..... eqn 2

adding eqn 1 & 2, we get 2x = 8

                                      x=4

                                      y=2

 

Original number =42

Answer 2

Answer:

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