Question

In a two digit number the sum of the digits is 7. If the number with the order of the digits reversed is 28 greater than twice the unit's digit of the original number, find the number​

Answer 1

Let the number be 10x + y

Given :

x + y = 7

y = 7 - x ... (1)

Also Given :

Reversed no. = 10y + x

and

10y + x = 28 + 2y

From (1) : y = 7 - x

10(7 - x) + x = 28 + 2(7 - x)

70 - 10x + x = 28 + 14 - 2x

70 - 9x = 42 - 2x

28 = 7x

x = 4

y = 7 - x

y = 7 - 4

y = 3

New no. = 10x + y

= 40 + 3

= 43

The answer is 43

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