Question

In a two digit number the sum of the digits is 7. If the number with the order of the
digits reversed is 28 greater than twice the unit's digit of the original number, find the
number.​

Answer 1

Answer:

43

Step-by-step explanation:

Let the digits be x and y

Sum of digits=x+y=7

so y=7-x -equation1

Now,let y be at tens place and x at ones place

So the number is 10y+x=10(7-x)+x from equation 1

the number is 70-9x

If we reverse the digits then ones in y and tens is x

So number become 10x+y=7+9x

Now according to que.the number obtained by reserving digits is 28 greater than twice the unit's digit of the original number So 7+9x=28+2

x

By solving it we get x=3 so y=7-3=4 so number is 43