In a two digit number the sum of the digits is 7. If the number with the order of the
digits reversed is 28 greater than twice the unit's digit of the original number, find the
number
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Answer:Let the two digit number be 10x+y,
And the reversed no. be 10y+x,
Given,
x+y=7 ---------(I)
according to the problem
10y+x=28+2y
x+8y=28 -------------(II)
x=4
y=3
Step-by-step explanation:
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