in a two digit number the sum of the digits is 8 . if 18 is added to the number it's digits are reversed. find the number .
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Step-by-step explanation:
let the digit at one s place be x
and tge digit at tens place be 8-x
the no.=10(8-x)±1(x)
=80-10x ±x
=80-9x
the reversed no.= 10(x) ±1(8-x)
=10x ±8-x
=9x±8
B/Q
80-9x±18=9x±8
=>98-9x=9x±8
=>-9x-9x=8-98
=>-18x=-90
=>x= -90÷-18
=>x=5
the no.=10(8-x)±1(x)
=80-50±5
=30±5
=35
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