Question

in a two digit number the sum of the digits is 8 . if 18 is added to the number it's digits are reversed. find the number .​

Answer 1

Step-by-step explanation:

let the digit at one s place be x

and tge digit at tens place be 8-x

the no.=10(8-x)±1(x)

=80-10x ±x

=80-9x

the reversed no.= 10(x) ±1(8-x)

=10x ±8-x

=9x±8

B/Q

80-9x±18=9x±8

=>98-9x=9x±8

=>-9x-9x=8-98

=>-18x=-90

=>x= -90÷-18

=>x=5

the no.=10(8-x)±1(x)

=80-50±5

=30±5

=35