In a two digit number the sum of the digits is 9. If tbe digits are reversed the number is increased by. Find the number
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Answer:
Let, m and n be the two digits.
Then:
m+n=9
10m+n+9=10n+m
n=9-m
Then:
10m+(9-m)+9=10(9-m)+m
9m+18=90–9m
18m=72
m=4
n=5
The number is 45.
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