In a two digit number the sum of the digits is nine. If the number is reversed then the new number is 9 less than 3 times the original number find the original number with explanation
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Step-by-step explanation:
Let the -
- ten's digit number be "M"
- one's digit number be "N"
In a two digit number the sum of the digits is nine.
According to question,
→ M + N = 9
→ M = 9 - N ___ (eq 1)
If the number is reversed then the new number is 9 less than 3 times the original number.
- Original number = 10M + N
- Revered number = 10N + M
According to question,
→ 10N + M = 3(10M + N) - 9
→ 10N + M = 30M + 3N - 9
→ 10N - 3N + M - 30M = - 9
→ 7N - 29M = - 9
→ 7N - 29(9 - N) = - 9
→ 7N - 261 + 29N = - 9
→ 36N = - 9 + 261
→ 36N = 252
→ N = 7
(One's digit = 7)
Substitute value of N in (eq 1)
→ M = 9 - 7
→ M = 2
(Ten's digit = 2)
So,
Original number = 10M + N
→ 10(2) + 7
→ 20 + 7
→ 27
∴ Original number is 27.
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