Question

In a two digit number the sum of the digits is seven if the digits are reversed the number obtained is 28 greater than twice the units digit of the original number find the number.

Answer 1

Answer:

ʟᴇᴛ ᴛʜᴇ ᴏʀɪɢɪɴᴀʟ ɴᴏ. ʙᴇ 10(7-x)+x

ʜᴇʀᴇ,X ɪs ᴏɴᴇs ᴅɪɢɪᴛ ᴀɴᴅ (7-x) ɪs ᴛʜᴇ ᴛᴇɴs ᴅɪɢɪᴛ ᴡʜɪᴄʜ ɪs ᴡᴇ ᴍᴜʟᴛɪᴘʟʏ ɪᴛ ᴡɪᴛʜ 10

ᴛʜᴇ ʀᴇᴠᴇʀsᴇᴅ ɴᴜᴍʙᴇʀ ᴡᴏᴜʟᴅ ᴡᴇ 10x+(7-x)

ᴡᴇ ᴋɴᴏᴡ,10x+(7-x)=28+2x

10x+7-x=28+2x

10x-2x-x=28-7

7x=21

x=3

ʜᴇɴᴄᴇ,ᴛʜᴇ ᴏʀɪɢɪɴᴀʟ.ɴᴏ. ɪs 10(7-3)+3=43

ᕼOᑭᗴ IT ᕼᗴᒪᑭՏ ᑌ...❤

Answer 2

Answer:

The original number is 43.

Step-by-step explanation:

Let the original number be 10( 7–x ) + x.

Here x is the one's digit and ( 7–x ) is the tens digit which is why we multiply it with 10.

The reversed number would be 10x + ( 7–x ).

We know that

10x + ( 7–x ) = 28 + 2x

10x –2x –x = 28 – 7

7x = 21

x = 3

Hence, the original number is

10 ( 7–3 ) + 3 = 43.

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