Question

In a two-digit number, the sum of the two digits is 12 and the digit in the tens place is thrice the digit in the ones
place.Find the digit in the ones place​

Answer 1

Answer:

let digit at ten's place be x

digit at one's place be y

x+y= 12→(1)

x=3y→(2)

putting this value of X in (1),

3y+y=12

4y=12

y=3

digit at one's place=3

digit at ten's place= 3×3

= 9

thus, the required number= 93

hope this helps

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