Question

In a two digit number the sum of two digits is 8 . If 18 is added to the number it's digits are reversed . find the number ?​

Answer 1

Given :

• Sum of two digit number is 8
• 18 is added to the number, the digits change their places.

To Find :

• The Number =?

Step-by-step explanation :

Let one's digit of the two digits number be x

Then, the ten's digit of the two digit number be 8 - x.

So, the number is, 10(8 - x) + x

After reversing the digits the number will be,

= 10x + (8 - x)

According to the question :

10x + (8 - x) + 18 = 10(8 - x) + x

10x + 8 - x + 18 = 80 -10x + x

9x + 26 = 80 - 9x

9x + 9x = 80 - 26

18x = 54

x = 54/18

x = 3

Hence,

One Number = x = 3

Other number = 8 - x = 8 - 3 = 5

Hence, the number is 35.

Answer 2

$\bf\large\mathfrak{\red{\underline{\underline{Question:-}}}}$

In a two digit number the sum of two digits is 8 . If 18 is added to the number it's digits are reversed . find the number ?

$\bf\large\mathfrak{\red{\underline{\underline{Gievn:-}}}}$

• sum of 2 digit is =8

• If 18 is added to the number it's digits are reversed.

$\bf\large\mathfrak{\pink{\underline{\underline{To\:Find:-}}}}$

• number =?

$\bf\large\mathfrak{\pink{\underline{\underline{Solution:-}}}}$

Let ,

• the 1st digit be x
• 10th digit of 2 number be (x-8)
• on reversing 10x(x+8)

$\bf\large\mathfrak{\green{\underline{\underline{According\:To\: Question:-}}}}$

$\tt→ 10x+(8-x)+18=10(8-x)+x\\\tt→ 10x+8-x+18=80x-x\\\tt→ 9x+26=80-9x\\\tt→ 18x=54\\\tt→x=\frac{54}{18}$

$\bf\large\mathfrak{\blue{\underline{\underline{Hence:-}}}}$

The required number is 3.