Question

In a two digit number the sum of two digitsis 8.if 18 is added to the number it's digits are reversed.find the number.

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Answer 1

Answer:

35

Step-by-step explanation:

Hi!!

Assume the number to be 10x+y

According to the question, x+y=8..................(1)

Also, 10x+y +18 = 10y+x (digits are reversed)

=>9x-9y= -18,

=>x-y= -2................................................................(2)

(1)+(2) => 2x=6,

         => x=3

  Substituting x value in (1),

    y=8-x=8-3=5

Thus the number is 35

Hope this helps!!

Answer 2

Answer:

Let the digit at ones place be ‘x’

Then the digit at tens place = 8 – x (sum of the two digits is 8)

Therefore number 10 (8 – x) + x = 80 – 10x + x = 80 – 9x —— (1)

Now, number obtained by reversing the digits = 10 ×(x) + (8 – x)

= 10x + 8 – x = 9x + 8

It is given that if 18 is added to the number its digits are reversed

∴ number + 18 = Number obtained by reversing the digits

⇒ (80 – 9x) + 18 = 9x + 8

98 – 9x = 9x + 8

98 – 8 = 9x + 9x

90 = 18x

x =

90

18 = 5

By substituting the value of x in equation (1) we get the number

∴ Number = 80 – 9 × 5 = 80 – 45 = 35.