In a two digit number, the ten’s digit is 7 the sum of the digit is 8 times the units digit. Find the number.
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Answer: Correct answer is
71
In the two digit number, let the digit in the units place is x and the digit in the tens place is 7.
∴ The number is 10(7)+x=70+x
Sum of digits =8 times the digit in the units place.
∴ Sum of both the digits =8× digit at units place
∴7+x=8×x
∴7=7x
∴x=1
Now, substituting x=1 in required number 70+x, we get
70+x=70+1=71
Step-by-step explanation:
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