Question

in a two digit number,the ten's digit is bigger. the product of the digit is 27 and the difference between two digits is 6. find the number​

Answer 1

let two digits be a and b

a×b=27 .....eq1

a=27÷b .....eq2

a-b=6 .....eq3

put eq2 in above equation

27÷b-b=6

(27-b2)÷b=6 #b2 is b square

27-b2=6b

b2+6b-27=0

solving simultaneous equation

b2+9b-3b-27=0

b(b+9)-3(b+9)

(b-3)(b+9)

b=3.....eq4

putting eq4 in eq3

a-b=6

a-3=6

a=6+3

a=9

Now the no. containing digits a and b= 93

hope u understand!!!