Question

in a two digit number the tens digit is one more in a two digit number the tens digit is one more than toys the unit digit the sum of the digits is 36 less than the number formed by reversing the digits find the product of the digit ​

Answer 1

Correct Question :

In a two digit number the tens digit is one more than twice the unit digit .

The sum of the digits is 36 less than the number formed by reversing the digits .

Find the product of the digits !

Solution :

Let us assume that the units digit of the two digit number is x .

The tens digit is one more than twice the units digit.

Thus , the tens digit becomes (2x + 1)

Number :

Tens Units

(2x + 1) (x)

The sum of the digits is 36 less than the number formed by reversing the digits .

> [ Sum of digits ] + 36 = [ Reversed Number ]

> [ 2x +1 + x] + 36 = [ 10x + 2x + 1]

> 3x + 1 + 36 = 12x + 1

> 9x = 36

> x = 4

2x + 1

> 2 × 4 + 1

> 9

Thus , the number becomes 94

[ Verification - ( 9 + 4 ) + 36 = 49 ]

This is the required answer .

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Answer 2

Answer:

Given :-

In a two digit number the tens digit is one more in a two digit number the tens digit is one more than toys the unit digit the sum of the digits is 36 less than the number formed by reversing the digits find the product of the digit

To Find :-

The Number

Solution :-

Let the digit at unit place be y.

Hence,

Tens = (2y + 1)

Now,

2y + 1 + y + 36 = 10y + 2y + 1

2y + y + 36 + 1 = 10y + 2y + 1

3y + 36 + 1 = 12y + 1

3y + 37 = 12y + 1

12y - 3y = 37 - 1

9y = 36

y = 36/4

y = 4

Now,

Ones formed = 2(4) - 1 = 9

$\huge \fbox{Number = 49}$