In a two digit number the tens digit is three times the unit digit.when the number is decreased by 54, the digit are reversed. Find the numbers
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Let us assume x is a tens digit and y is ones place digit are the two digits of a two digit number
Therefore, the number is 10x + y and reverse number is 10y + x
Given:
x = 3y ------------1
Also given:
10x + y – 54 = 10y + x
9x – 9y = 54
x – y = 6 -------------2
substitute the value of x from equation 1 in equation 2
3y – y = 6
2y = 6
y = 3
Therefore, x = 3 * y = 3 * 3 = 9
Therefore, the two-digit number = 10x + y = (10*9) + 3 = 93
and the reversed number = 10y + x = (10 *3) + 9 = 39
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