Math, asked by bhavishyadevineni9, 14 hours ago

In a two digit number, the tens digit is twice the unit digit. When the digits are reversed, the new number formed is 18 less than the original number. The original number is ​

Answers

Answered by rudrapratapsingh1233
0

Given:

The tens digit of a two digit number is twice of its units digit

On reversing the digits, the number formed is 27 less than the original number

To find: the original number

Solution:

Let the digits in units and tens places be x and y.

Then the number is y + 10x

When the digits are reversed, the number becomes x + 10y

By the given conditions,

y = 2x ... ...(i)

y + 10x = x + 10y - 27

or, 2x + 10x = x + 10 * 2x - 27 [using (i)]

or, 12x = x + 20x - 27

or, 21x - 12x = 27

or, 9x = 27

or, x = 3

Putting x = 3 in (i), we get

y = 2 * 3

or, y = 6

Thus the original number is

y + 10x = 6 + 10 * 3 = 6 + 30 = 36

Answer: the original number is 36

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