Question

in a two digit number the tens digit is two more than the unit digit sum of the digits is 1 by 7 of the whole number then the number is​

Answer 1

||✪✪ QUESTION ✪✪||

in a two digit number the tens digit is two more than the unit digit sum of the digits is 1 by 7 of the whole number then the number is ?

|| ✰✰ ANSWER ✰✰ ||

Let the Unit digit be x and ten's digit be y .

So, the Two digit Number is = (10y + x).

Now, it has been said that, tens digit is two more than the unit digit ,

So,

→ y = x + 2

→ y - x = 2 ------------------- Equation (1) .

Now, it has been said that, sum of the digits is 1 / 7 of the whole number.

So,

→ (x + y) = 1/7(10y+x)

→ 7x + 7y = 10y + x

→ 7x - x = 10y - 7y

→ 6x = 3y

Dividing both sides by 3 , we get,

→ 2x = y ------------------ Equation (2)

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Putting value of Equation (2) , in Equation (1) now we get,

→ 2x - x = 2

→ x = 2 .

putting this value in Equation (2) now, we get,

→ y = 2x = 2*2 = 4.

Hence, the Required Number is ,

→ 10y + x

→ 10*4 + 2

→ 40 + 2

→ 42. (Ans).

Answer 2

$\large{\underline{\underline{\mathfrak{\bf{\:QUESTION:-}}}}}$

• in a two digit number the tens digit is two more than the unit digit sum of the digits is 1 by 7 of the whole number then the number is..?

$\large{\underline{\underline{\mathfrak{\bf{\:SOLUTION:-}}}}}$

$\large{\underline{\:GIVEN\:HERE:-}}$

• in a two digit number the tens digit is two more than the unit digit .

• sum of the digits is 1 by 7 of the whole number .

_______________________

$\large{\underline{\:FIND\:HERE:-}}$

• Find the two digit number(10y+x) .

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$\large{\underline{\underline{\mathfrak{\bf{\:\:\:\:\:\:EXPLANATION:-}}}}}$

Let, Unit digit is x and tens digit is y .

So, Number will be = (10y+x) .

Now, A/C to question,

$\bold{\boxed{\boxed{\:y\:=\:(x+2)}}}$

$\leadsto\:(y-x)\:=\:2$.....(1)

again, A/C to queation,

$\bold{\boxed{\boxed{\:(x+y)\:=\frac{1}{7}\times(10y+x)}}}$

$\leadsto\:(7x+7y)\:=\:(10y+x)$

$\leadsto\:(10y-7y)\:=\:(7x-x)$

$\leadsto\:(3y)\:=\:(6x)$

$\leadsto\:y\:=\frac{\cancel{6}\times\:x}{\cancel{3}}$

$\bold{\boxed{\boxed{\:y\:=\:2x}}}$...(2)

keep value of y in equation (1),

$\leadsto\:(-x+2x)\:=\:2$

$\bold{\boxed{\boxed{\:x\:=\:2}}}$

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keep value of x in equation (2),

$\leadsto\:y\:=\:2\times\:2$

$\bold{\boxed{\boxed{\:y\:=\:4}}}$

So ,required Number will be

$\leadsto\:(10y+x)\:=\:(10\times4\:+\:2)$

$\bold{\boxed{\boxed{\:(10y+x)\:=\:(42)}}}$

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