in a two digit number, the unit digit is 4 less than the tens digit. the original number is 7 less than 8 times the sum of digit find the three times of the number.
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Answer:
A 22 digit number is written in the form dtens digitdones digit∣dtens digit>0dtens digitdones digit∣dtens digit>0 meaning dtens digit×101+dones digit×100dtens digit×101+dones digit×100 now your condition is that dones digit=dtens digit−4dones digit=dtens digit−4
So dtens digit≥4dtens digit≥4 for dones digitdones digit to be valid. So the numbers are:
40,51,62,73,8440,51,62,73,84 and 9595.
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Irish Irojo
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Sandeep Vijay
, works at Cipla
Answered 4 years ago · Author has 264 answers and 666.3K answer views
Answer:
28
Step-by-step explanation:
number =y×10+x
x=4(y)....(1)
y+x=10...(2)
y+4y=10
5y=4y=10⇒y=2
x=8
Number =20+8=28
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