Question

In a two digit number the unit digit is four times the ten digit and the sum of the two digit is 10.find the number.​

Answer 1

Step-by-step explanation:

Let number at unit place be x.

And digit at tens place y.

The number=10y+x

According to question,

x=40y. ....,..........1

x+10y=10…....………2

Multiply equation 2 by 4

4x+40y=40… ........3

x-40y=0……………4

Adding

4x+40y=40

+. x-40y=0

=x=8

put in equation 4

y=2

Answer 2

✬ Number = 28 ✬

Step-by-step explanation:

Given:

• In a number the unit digit is four times the tens digit.
• Sum of the digits of the number is 10.

To Find:

• What is the number?

Solution: Let the tens digit be x.

∴ Unit's digit = 4 times of x = 4x

• Sum of number is 10. i.e
• x + 4x = 10

Therefore the number will be x + 4x = 10

$\small\implies{\sf }$ x + 4x = 10

$\small\implies{\sf }$ 5x = 10

$\small\implies{\sf }$ x = 10/5

$\small\implies{\sf }$ x = 2

∴ Tens digit = x = 2 and

Unit's digit = 4x = 4(2) = 8

Hence, The required number is (10 x 2 + 8) = 28.