In a two Digit number. the unit digit is thrice the ten digit,if 36 is added to the number ,the digit interchange their place.find the number.
Answers
Answer:
Given,
In a two digit number, the units digit is thrice the tens digit.
Let the number be "ab"
⇒ b = 3a
Therefore, we have,
ab = 10a+b
When 36 is added to the number, the digits interchange their place.
⇒ 10a + b + 36 = 10b + a
substituting b = 3a, we get,
10a + 3a + 36 = 10(3a) + a
10a + 3a + 36 = 30a + a
13a + 36 = 31a
36 = 31a - 13a
36 = 18a
a = 36/18
∴ a = 2
b = 3 × 2
∴ b = 6
Therefore, the required number is 26
Verification:
We have,
ab = 26
26 + 36 = 62
Answer:
26
Step-by-step explanation:
Let ht etens digit be x and units digit be y.
The number will be: 10x+y
If we add 36, the result is: 10y+x
- y=3x
=> 10x+y+36=10y+x
=> 10x+3x +36= 10(3x)+x
=> 13x+36=31x
=> 13x-31x=(-36)
=> -18x= -36
=> x= 36/18 [minus cancelled]
=> x=2
Therefore, the tens digit is 2 and units digit is (2*3)= 6
The number is 26.