In a two digit number, the unit's digit is 1 more than twice the ten's digit. If the order of the digits is reversed, the new number is 36 more than the given number. Find the given number.
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Let us assume, x and y are the two digits of the two-digit number, where y is the unit place digit and x is the tenth place digit
Therefore, the two-digit number = 10x + y and the reversed number = 10y + x
Given:
y = 2x + 1 ----------------------1
also given:
10y + x = 10x + y + 36
9y - 9x = 36
y - x = 4 ----------------------2
Substitute the value of y from equation 1 in equation 2
2x + 1 - x = 4
x = 3
Therefore, y = 2x + 1 = 2 * 3 + 1 = 7
Therefore, the two-digit number = 10x + y = 10*3 + 5 = 37
Answer - The number = 37
Therefore, the two-digit number = 10x + y and the reversed number = 10y + x
Given:
y = 2x + 1 ----------------------1
also given:
10y + x = 10x + y + 36
9y - 9x = 36
y - x = 4 ----------------------2
Substitute the value of y from equation 1 in equation 2
2x + 1 - x = 4
x = 3
Therefore, y = 2x + 1 = 2 * 3 + 1 = 7
Therefore, the two-digit number = 10x + y = 10*3 + 5 = 37
Answer - The number = 37
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