in a two digit number, the units digit is 2 more than that of tens digit. the sum of the digits is 27 less than the number. find the product of the digits of the number.
a) 8
b) 15
c) 24
d) 35
Answers
Step-by-step explanation:
we have (c and b) optins as the only option possible for rquation looking by unit digit is tens digit + 2
we see that on minusing 27 from 24 results in negative number
now lets see d option
35 = 3+5 = 8 => 27+8 = 35
hence d (35) is answer
Answer:
The correct option is option (b)
Step-by-step explanation:
Let the units digit be x
and the tens digit be y
Therefore the number will be 10y + x
Given that units digit is 2 more than tens digit
=> x = 2 + y
and the sum of the digits is 27 less than the number
=> x + y = 10y + x - 27
On solving,
=> y = 10y - 27
=> 27 = 10y - y
=> 27 = 9y
=> 3 = y
Therefore, the tens digit is 3
As x = 2 + y
= 2 + 3
= 5
Therefore, the units digit is 5
We need to find the product of digits of the number
=> 3 * 5 = 15
Therefore, the product of digits of the number = 15
The correct option is option (b)