in a two digit number, the units digit is 5 less than the tens digit. if the number is equal to 10 times the sum of its digits .find the number
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999999999999999999999
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Answer:
Let the two no.s be a,b
Given,
a>b
(a+b)=2(a−b)
⟹a=3b
Put values of b such that a<10 (otherwise it would be a 3 digit number)
b=1,2,3
a=3,6,9
So, the possible numbers are 31,62,93.
Hence, 3 such numbers are possible
hope it helps you
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