Question

in a two digit number the units digit is four times the tens digit and the sum of digits is 10 find the number

Answer 1

Answer is 28

Let the tens digit be x and units digit be y
therefore the digit is xy

Unit digit is 4 times the tens digit
therefore y = 4x
4x - y = 0

The sum of both the digits is 10
Hence x + y = 10

Calculating (Adding) both the equations
5x = 10
x = 2

Solving the above (any one) equation, we get
y = 8

therefore the number is 28.

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Answer 2

$\huge\underline\mathrm{GivEn:-}$

⭐ the units digit is four times the tens digit

⭐ the sum of digits is 10

$\huge\underline\mathrm{To \: Find:-}$

↪ find the number =?

$\huge\underline\mathrm{SoLutioN:-}$

Let the digit in the unit's place be 'y' and digit in the ten's place be 'x' . Then,

$\implies$ y = 4x __1)

and,

Number = 10x + y

According to question

The sum of digits is 10

$\implies$ x + y = 10 ___2)

put the value of 'y' in equation 2)

$\implies$ x + 4x = 10

$\implies$ 5x = 10

$\implies$ x = $\large{\sf {\frac{10}{5}}}$

$\large{\boxed{\bf{x\: = \: 2}}}$

put the value of x in equation 1).

$\implies$ y = 4(2)

$\large{\boxed{\bf{y\: = \: 8}}}$

Hence the number is = 10x + y

$\implies$ 10(2)+8

$\implies$ 20+8

$\large{\boxed{\bf{Number\: =\:28}}}$

$\huge\underline\mathrm{Verification:-}$

put the value of 'x' and 'y' in equation 1)

⚫ value of x = 2

⚫ value of y = 8

$\implies$ y = 4x

$\implies$ 8 = 4(2)

$\implies$ 8 = 8

put the value of 'x' and 'y' in equation 2)

$\implies$ x + y = 10

$\implies$ 2 + 8 = 10

$\implies$ 10 = 10

$\huge\underline{Verified}$✔

$\huge\underline\mathrm{ThAnKs...}$