Math, asked by sushant125098, 10 months ago

In a two digit number. The units digit is thrice the tens digit. If 36 is added to the number, the digits interchange their place. Find the number.

Answers

Answered by Sauron
77

Answer:

The Orignal Number is 62.

Step-by-step explanation:

Given :

Units digits is thrice the tens digit

The digits interchange when - 36 is added

To find :

The number

Solution :

\textsf{\underline{\underline{Original Number,}}}

Let the digits be -

  • Units place as 3y
  • Tens place as 10(y)

⇒ 10(y) + 3y

⇒ 10y + 3y

13y --------- (Orignal Number)

\rule{300}{1.5}

\textsf{\underline{\underline{Number with reversed digits,}}}

Let the digits be -

  • Units place as y
  • Tens place as 10(3y)

⇒ 10(3y) + y

⇒ 30y + y

31y --------- (Number with reversed digits)

\rule{300}{1.5}

\textsf{\underline{\underline{According to the question,}}}

The number gets reversed when 36 is added to it.

⇒ 13y + 36 = 31y

⇒ 13y - 31y = - 36

⇒ 18y = 36

⇒ y = 36/18

y = 2

\rule{300}{1.5}

\textsf{\underline{\underline{Orignal Number,}}}

⇒ 13y

⇒ 13(2)

26

\rule{300}{1.5}

\textsf{\underline{\underline{Verification,}}}

The units place should be thrice of the tens place,

⇒ 2 × 3 = 6

Units place is 6

Reversed digits are 62,

⇒ 26 + 36 = 62

62 = 62

\therefore The Orignal Number is 62.


StarrySoul: Nice One! :D
Sauron: Thanks a lot! ♡
Answered by StarrySoul
113

Solution :

Let the digit at tens place be x and digit at ones place be y

Given that units digit is thrice the tens digit i.e.

 \sf \: y = 3x....(i)

 \star \sf \: Original  \: Number = 10x +y

 \star \sf \:  Interchanged \: Number = 10y +x

According to the Question :

 \longrightarrow \sf \: 10x + y + 36 = 10y + x

Putting the value of equation i)

 \longrightarrow \sf \: 10x + 3x + 36 = 10(3x)+ x

 \longrightarrow \sf \: 13x + 36 = 30x+ x

 \longrightarrow \sf \: 13x + 36 = 31x

 \longrightarrow \sf \: 13x  - 31x =  - 36

 \longrightarrow \sf \: 13x  - 31x =  - 36

 \longrightarrow \sf \:  - 18x =  - 36

 \longrightarrow \sf \:  x =   \cancel\dfrac{ - 36}{ - 18}

 \longrightarrow \sf  \red{\:  x = 2}

Putting the value of x = 2 in equation i)

 \sf \: y = 3 \times 2

 \longrightarrow  \red{\sf \: y = 6}

________________________________

 \star \sf \: Original  \: Number = 10(2)+6 =  \boxed{ \sf \: 26}

 \star \sf \:  Interchanged \: Number = 10(6) +2 =  \boxed{ \sf \: 62}


Sauron: Awesomeeeee :0
StarrySoul: Thankss! ♥️
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