Question

in a two digit number unit digit is 3 less than the tens digit number is greater than 3 of the 7 times of sum of the digit find the number

Answer 1

$\huge{\bf{\underline{\green{Answer :}}}}$

Let the ten's place digit = x

So unit place digit = x - 3

So we know that :

Number = 10 × tens digit + Unit digit

⇒ 10 × x + x - 3

⇒11x - 3 .........1] Equation

Sum of the  digits = ( x + x - 3)

According to the  given condition in question :

∴ ⇒ 11x - 3 = 7( x + x - 3 ) + 3

⇒11x - 3 = 7x + 7x -21 + 3

⇒11x - 7x -7x = -21 +3 + 3

⇒ -3x = - 15

x = -15/-3

x = 5

Now the value of x put in first equation :

∴ ⇒ 11x -3

⇒ 11 × 5 -3

⇒ 55 -3

52 (Answer)