In a two digit number unit digit is 3 more than double of ten's digit.If by
interchanging the digits a new number is obtained which is 15 more than the
double of the original number. Find original number.
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Step-by-step explanation:
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Answer:
The number is 39.
Step-by-step explanation:
let the number on unit place be 'x' and the number on tenth place be 'y'.
As per the first given condition,
x= 2y + 3 …………………(1)
As per second given condition
2 (10y + x) + 15 = 10x + y
20y + 2x +15 = 10x + y
8x - 19y = 15 ………………………(2)
Now,
putting (2) in (1), we get
16y + 24 - 19y = 15
-3y = -9
y=3. _______________(3)
putting (3) in (1), we get
x = 6+3
x=9
hence the number is 39...
(If your mood is good and fundamentals too then you will understand)
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